What is the answer to 8x^2-(2x+3)(4x-5)=1 ?

The answer to 8x^2-(2x+3)(4x-5)=1 is x=7

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8x^2-(2x+3)(4x-5)=1

8 x^{2} - (2 x + 3) (4 x - 5) = 1

x = 7

Solution steps

8 x^{2} - (2 x + 3) (4 x - 5) = 1

Expand

- (2 x + 3) (4 x - 5) : - 8 x^{2} - 2 x + 15

8 x^{2} - 8 x^{2} - 2 x + 15 = 1

Add similar elements:

8 x^{2} - 8 x^{2} = 0

- 2 x + 15 = 1

Move

15

to the right side

- 2 x = - 14

Divide both sides by

- 2

x = 7

3 x^{3} + 2 x^{2} - 7 x + 2

\frac{5}{2 i}

3^{x - 8} \leq 9

(4.9 - 4.18) \cdot 0.5 \cdot 0.3

∣ 4 y - 7 ∣ \geq 8

What is the answer to 8x^2-(2x+3)(4x-5)=1 ?
The answer to 8x^2-(2x+3)(4x-5)=1 is x=7
Solve for x: 8x^2-(2x+3)(4x-5)=1
The solution is x=7