What are the solutions to the equation (2x-1)(x+2)=0 ?

The solutions to the equation (2x-1)(x+2)=0 are x= 1/2 ,x=-2

Find the zeros of (2x-1)(x+2)=0

The zeros of (2x-1)(x+2)=0 are x= 1/2 ,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2 x - 1) (x + 2) = 0

x = \frac{1}{2}, x = - 2

Decimal Notation

x = 0.5, x = - 2

Solution steps

(2 x - 1) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0 or x + 2 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x + 2 = 0 : x = - 2

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 2

\frac{n}{2} + 2 = 10

\frac{4}{- 8}

4 n + 11 > - 9

x^{3} - 2 x^{2} - 9 x + 18

What are the solutions to the equation (2x-1)(x+2)=0 ?
The solutions to the equation (2x-1)(x+2)=0 are x= 1/2 ,x=-2
Find the zeros of (2x-1)(x+2)=0
The zeros of (2x-1)(x+2)=0 are x= 1/2 ,x=-2