What are the solutions to the equation 4x^2+25=20x ?

The solutions to the equation 4x^2+25=20x are x= 5/2

Find the zeros of 4x^2+25=20x

The zeros of 4x^2+25=20x are x= 5/2

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4 x^{2} + 25 = 20 x

x = \frac{5}{2}

Decimal Notation

x = 2.5

Solution steps

4 x^{2} + 25 = 20 x

Move

20 x

to the left side

4 x^{2} + 25 - 20 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 20 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 25 = 0

x_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 20 )}{2 \cdot 4}

\frac{- ( - 20 )}{2 \cdot 4} = \frac{5}{2}

x = \frac{5}{2}

The solution to the quadratic equation is:

x = \frac{5}{2}

\frac{t + 1}{7} > - 1

\frac{1}{2} x^{2} - x - 4 = 0

\frac{x - 2}{x + 3} \leq 0

2 (5 x + 7) = 34

What are the solutions to the equation 4x^2+25=20x ?
The solutions to the equation 4x^2+25=20x are x= 5/2
Find the zeros of 4x^2+25=20x
The zeros of 4x^2+25=20x are x= 5/2