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Popular >

2(4x-1)^2+(4x-1)>= 0

Solution

2 (4 x - 1)^{2} + (4 x - 1) \geq 0

Solution

x \leq \frac{1}{8} or x \geq \frac{1}{4}

+2

Interval Notation

(- \infty, \frac{1}{8}] \cup [\frac{1}{4}, \infty)

Decimal Notation

x \leq 0.125 or x \geq 0.25

Solution steps

2 (4 x - 1)^{2} + 4 x - 1 \geq 0

Factor

2 (4 x - 1)^{2} + 4 x - 1 : (4 x - 1) (8 x - 1)

(4 x - 1) (8 x - 1) \geq 0

Identify the intervals

x \leq \frac{1}{8} or x \geq \frac{1}{4}

Popular Examples

3 x^{2} - 15 x = 0

factor 2x^2-3x-2 factor

2 x^{2} - 3 x - 2

simplify 2(12/13)^2-1 simplify

2 (\frac{12}{13})^{2} - 1

(x^2-2)=(4x+10)

(x^{2} - 2) = (4 x + 10)

simplify 2(-1/2)simplify

2 (- \frac{1}{2})

Frequently Asked Questions (FAQ)

What is 2(4x-1)^2+(4x-1)>= 0 ?
The solution to 2(4x-1)^2+(4x-1)>= 0 is x<= 1/8 \lor x>= 1/4