What are the solutions to the equation (g-11)(g-5)=35 ?

The solutions to the equation (g-11)(g-5)=35 are g=2(4+sqrt(11)),g=2(4-sqrt(11))

Find the zeros of (g-11)(g-5)=35

The zeros of (g-11)(g-5)=35 are g=2(4+sqrt(11)),g=2(4-sqrt(11))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(g - 11) (g - 5) = 35

g = 2 (4 + 11), g = 2 (4 - 11)

Decimal Notation

g = 14.63324 \dots, g = 1.36675 \dots

Solution steps

(g - 11) (g - 5) = 35

Expand

(g - 11) (g - 5) : g^{2} - 16 g + 55

g^{2} - 16 g + 55 = 35

Move

35

to the left side

g^{2} - 16 g + 20 = 0

Solve with the quadratic formula

g_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 20 = 411

g_{1, 2} = \frac{- ( - 16 ) \pm 4 11}{2 \cdot 1}

Separate the solutions

g_{1} = \frac{- ( - 16 ) + 4 11}{2 \cdot 1}, g_{2} = \frac{- ( - 16 ) - 4 11}{2 \cdot 1}

g = \frac{- ( - 16 ) + 4 11}{2 \cdot 1} : 2 (4 + 11)

g = \frac{- ( - 16 ) - 4 11}{2 \cdot 1} : 2 (4 - 11)

The solutions to the quadratic equation are:

g = 2 (4 + 11), g = 2 (4 - 11)

- 2 + 3 (- 1) \geq \frac{1}{3}

x^{2} - x > 20

38 x + 40 + 120 x = 34 x - 7 (20 - 19 x)

3 x - 2 - 3 (- 1 + 2 x) = 2 - 2 (x - 1)

What are the solutions to the equation (g-11)(g-5)=35 ?
The solutions to the equation (g-11)(g-5)=35 are g=2(4+sqrt(11)),g=2(4-sqrt(11))
Find the zeros of (g-11)(g-5)=35
The zeros of (g-11)(g-5)=35 are g=2(4+sqrt(11)),g=2(4-sqrt(11))