What is |2x-1|>= |x+1| ?

The solution to |2x-1|>= |x+1| is x = 2

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|2x-1|>= |x+1|

∣ 2 x - 1 ∣ \geq ∣ x + 1 ∣

x \leq 0 or x \geq 2

Interval Notation

(- \infty, 0] \cup [2, \infty)

Solution steps

∣ 2 x - 1 ∣ \geq ∣ x + 1 ∣

Find positive and negative intervals

x < - 1, - 1 \leq x < \frac{1}{2}, x \geq \frac{1}{2}

Solve the inequality for each interval

x < - 1 or - 1 \leq x \leq 0 or x \geq 2

Merge Overlapping Intervals

x \leq 0 or x \geq 2

48 m^{2} - 38 m - 18

516

x^{5} - 5 x^{4} + 2 x^{3} + 14 x^{2} - 3 x - 9 < 0

∣ x - 4 ∣ < - 1

8^{\frac{1}{4}} \cdot 8^{\frac{1}{4}}