What are the solutions to the equation 4x^2+5=0 ?

The solutions to the equation 4x^2+5=0 are x=(sqrt(5))/2 i,x=-(sqrt(5))/2 i

Find the zeros of 4x^2+5=0

The zeros of 4x^2+5=0 are x=(sqrt(5))/2 i,x=-(sqrt(5))/2 i

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4 x^{2} + 5 = 0

x = \frac{5}{2} i, x = - \frac{5}{2} i

Solution steps

4 x^{2} + 5 = 0

Move

5

to the right side

4 x^{2} = - 5

Divide both sides by

4

x^{2} = - \frac{5}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{5}{4}, x = - - \frac{5}{4}

- \frac{5}{4} = \frac{5}{2} i

- - \frac{5}{4} = - \frac{5}{2} i

x = \frac{5}{2} i, x = - \frac{5}{2} i

6^{- 4}

∣ 2 x + 3 ∣ < 5

x^{2} + 11 = 0

63 - 175 + 4112

- 3 t^{2} + 11 t - 6

What are the solutions to the equation 4x^2+5=0 ?
The solutions to the equation 4x^2+5=0 are x=(sqrt(5))/2 i,x=-(sqrt(5))/2 i
Find the zeros of 4x^2+5=0
The zeros of 4x^2+5=0 are x=(sqrt(5))/2 i,x=-(sqrt(5))/2 i