What are the solutions to the equation 7m^2-2m=6 ?

The solutions to the equation 7m^2-2m=6 are m=(1+sqrt(43))/7 ,m=(1-sqrt(43))/7

Find the zeros of 7m^2-2m=6

The zeros of 7m^2-2m=6 are m=(1+sqrt(43))/7 ,m=(1-sqrt(43))/7

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7 m^{2} - 2 m = 6

m = \frac{1 + 43}{7}, m = \frac{1 - 43}{7}

Decimal Notation

m = 1.07963 \dots, m = - 0.79391 \dots

Solution steps

7 m^{2} - 2 m = 6

Move

6

to the left side

7 m^{2} - 2 m - 6 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 7 ( - 6 )}{2 \cdot 7}

(- 2)^{2} - 4 \cdot 7 (- 6) = 243

m_{1, 2} = \frac{- ( - 2 ) \pm 2 43}{2 \cdot 7}

Separate the solutions

m_{1} = \frac{- ( - 2 ) + 2 43}{2 \cdot 7}, m_{2} = \frac{- ( - 2 ) - 2 43}{2 \cdot 7}

m = \frac{- ( - 2 ) + 2 43}{2 \cdot 7} : \frac{1 + 43}{7}

m = \frac{- ( - 2 ) - 2 43}{2 \cdot 7} : \frac{1 - 43}{7}

The solutions to the quadratic equation are:

m = \frac{1 + 43}{7}, m = \frac{1 - 43}{7}

2 \cdot (\frac{1}{2})^{2}

∣ 8 - 4 x ∣ - 6 = 6

a x^{3} + b y^{3} + b x^{3} + a y^{3}

y^{2} - 3 y - 4

\frac{4}{5} - \frac{3}{10} m = \frac{1}{10} m - \frac{4}{5}

What are the solutions to the equation 7m^2-2m=6 ?
The solutions to the equation 7m^2-2m=6 are m=(1+sqrt(43))/7 ,m=(1-sqrt(43))/7
Find the zeros of 7m^2-2m=6
The zeros of 7m^2-2m=6 are m=(1+sqrt(43))/7 ,m=(1-sqrt(43))/7