What are the solutions to the equation x^2+4x=-7 ?

The solutions to the equation x^2+4x=-7 are x=-2+sqrt(3)i,x=-2-sqrt(3)i

Find the zeros of x^2+4x=-7

The zeros of x^2+4x=-7 are x=-2+sqrt(3)i,x=-2-sqrt(3)i

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x^{2} + 4 x = - 7

x = - 2 + 3 i, x = - 2 - 3 i

Solution steps

x^{2} + 4 x = - 7

Move

7

to the left side

x^{2} + 4 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 7 : 23 i

x_{1, 2} = \frac{- 4 \pm 2 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 3 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 3 i}{2 \cdot 1}

x = \frac{- 4 + 2 3 i}{2 \cdot 1} : - 2 + 3 i

x = \frac{- 4 - 2 3 i}{2 \cdot 1} : - 2 - 3 i

The solutions to the quadratic equation are:

x = - 2 + 3 i, x = - 2 - 3 i

e x > 7

2 x^{3} + 2 x^{2} - 12 x

a x + a y - x - y

2 x + 3 < 7 - 3 x \leq - 17

What are the solutions to the equation x^2+4x=-7 ?
The solutions to the equation x^2+4x=-7 are x=-2+sqrt(3)i,x=-2-sqrt(3)i
Find the zeros of x^2+4x=-7
The zeros of x^2+4x=-7 are x=-2+sqrt(3)i,x=-2-sqrt(3)i