What is factor 4x^3+4x^2-9x-9 ?

The solution to factor 4x^3+4x^2-9x-9 is (x+1)(2x+3)(2x-3)

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factor 4x^3+4x^2-9x-9

factor

4 x^{3} + 4 x^{2} - 9 x - 9

(x + 1) (2 x + 3) (2 x - 3)

Solution steps

4 x^{3} + 4 x^{2} - 9 x - 9

= (4 x^{3} + 4 x^{2}) + (- 9 x - 9)

Factor out

4 x^{2}

from

4 x^{3} + 4 x^{2} : 4 x^{2} (x + 1)

Factor out

- 9

from

- 9 x - 9 : - 9 (x + 1)

= 4 x^{2} (x + 1) - 9 (x + 1)

Factor out common term

x + 1

= (x + 1) (4 x^{2} - 9)

Factor

4 x^{2} - 9 : (2 x + 3) (2 x - 3)

= (x + 1) (2 x + 3) (2 x - 3)

4 x^{2} - 27 = 0

- \frac{15}{( 5 ( - 1 ) + 2 ) ^{2}}

x^{2} + 5 x = 0

\frac{x}{x - 5} - 2 \geq 0

\frac{12 !}{( 12 - 3 ) ! \cdot 3 !}

What is factor 4x^3+4x^2-9x-9 ?
The solution to factor 4x^3+4x^2-9x-9 is (x+1)(2x+3)(2x-3)