What are the solutions to the equation 4x^2-27=0 ?

The solutions to the equation 4x^2-27=0 are x=(3sqrt(3))/2 ,x=-(3sqrt(3))/2

Find the zeros of 4x^2-27=0

The zeros of 4x^2-27=0 are x=(3sqrt(3))/2 ,x=-(3sqrt(3))/2

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4 x^{2} - 27 = 0

x = \frac{3 3}{2}, x = - \frac{3 3}{2}

Decimal Notation

x = 2.59807 \dots, x = - 2.59807 \dots

Solution steps

4 x^{2} - 27 = 0

Move

27

to the right side

4 x^{2} = 27

Divide both sides by

4

x^{2} = \frac{27}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{27}{4}, x = - \frac{27}{4}

\frac{27}{4} = \frac{3 3}{2}

- \frac{27}{4} = - \frac{3 3}{2}

x = \frac{3 3}{2}, x = - \frac{3 3}{2}

- \frac{15}{( 5 ( - 1 ) + 2 ) ^{2}}

x^{2} + 5 x = 0

\frac{x}{x - 5} - 2 \geq 0

\frac{12 !}{( 12 - 3 ) ! \cdot 3 !}

- 12 d \geq - 6

What are the solutions to the equation 4x^2-27=0 ?
The solutions to the equation 4x^2-27=0 are x=(3sqrt(3))/2 ,x=-(3sqrt(3))/2
Find the zeros of 4x^2-27=0
The zeros of 4x^2-27=0 are x=(3sqrt(3))/2 ,x=-(3sqrt(3))/2