What is 35x^2-835x+2700>= 0 ?

The solution to 35x^2-835x+2700>= 0 is x = 20

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35x^2-835x+2700>= 0

35 x^{2} - 835 x + 2700 \geq 0

x \leq \frac{27}{7} or x \geq 20

Interval Notation

(- \infty, \frac{27}{7}] \cup [20, \infty)

Decimal Notation

x \leq 3.85714 \dots or x \geq 20

Solution steps

35 x^{2} - 835 x + 2700 \geq 0

Rewrite in standard form

7 x^{2} - 167 x + 540 \geq 0

Factor

7 x^{2} - 167 x + 540 : (7 x - 27) (x - 20)

(7 x - 27) (x - 20) \geq 0

Identify the intervals

x \leq \frac{27}{7} or x \geq 20

- 2 (x + 3) - 3 x < 7 (x - 4) + x

\frac{1}{2} = e^{\frac{1}{2} (0)^{2}}

∣ x ∣ + 8 \geq - 5

15 (x + 2) = 6

- 6 - (- 2)

What is 35x^2-835x+2700>= 0 ?
The solution to 35x^2-835x+2700>= 0 is x<= 27/7 \lor x>= 20