What are the solutions to the equation 0=-16t^2+80t ?

The solutions to the equation 0=-16t^2+80t are t=0,t=5

Find the zeros of 0=-16t^2+80t

The zeros of 0=-16t^2+80t are t=0,t=5

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0 = - 16 t^{2} + 80 t

t = 0, t = 5

Solution steps

0 = - 16 t^{2} + 80 t

Switch sides

- 16 t^{2} + 80 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

8 0^{2} - 4 (- 16) \cdot 0 = 80

t_{1, 2} = \frac{- 80 \pm 80}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 80 + 80}{2 ( - 16 )}, t_{2} = \frac{- 80 - 80}{2 ( - 16 )}

t = \frac{- 80 + 80}{2 ( - 16 )} : 0

t = \frac{- 80 - 80}{2 ( - 16 )} : 5

The solutions to the quadratic equation are:

t = 0, t = 5

5 x^{2} - 20 x

14 x^{2} - 17 x - 6

- 6 + 9 (8 - 2 b)

\frac{a}{3} \geq - 9

- \frac{3}{5} + \frac{1}{3}

What are the solutions to the equation 0=-16t^2+80t ?
The solutions to the equation 0=-16t^2+80t are t=0,t=5
Find the zeros of 0=-16t^2+80t
The zeros of 0=-16t^2+80t are t=0,t=5