What are the solutions to the equation 16x^2=81 ?

The solutions to the equation 16x^2=81 are x= 9/4 ,x=-9/4

Find the zeros of 16x^2=81

The zeros of 16x^2=81 are x= 9/4 ,x=-9/4

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16 x^{2} = 81

x = \frac{9}{4}, x = - \frac{9}{4}

Decimal Notation

x = 2.25, x = - 2.25

Solution steps

16 x^{2} = 81

Divide both sides by

16

x^{2} = \frac{81}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{81}{16}, x = - \frac{81}{16}

\frac{81}{16} = \frac{9}{4}

- \frac{81}{16} = - \frac{9}{4}

x = \frac{9}{4}, x = - \frac{9}{4}

∣ 2 x - 7 ∣ = 19

∣ 7 x + 2 ∣ = 12

5 x^{2} + 7 x - 12 = 0

2 h > 8

\frac{x}{4} - 17 = 18

What are the solutions to the equation 16x^2=81 ?
The solutions to the equation 16x^2=81 are x= 9/4 ,x=-9/4
Find the zeros of 16x^2=81
The zeros of 16x^2=81 are x= 9/4 ,x=-9/4