What are the solutions to the equation (2x-3)(x+4)=0 ?

The solutions to the equation (2x-3)(x+4)=0 are x= 3/2 ,x=-4

Find the zeros of (2x-3)(x+4)=0

The zeros of (2x-3)(x+4)=0 are x= 3/2 ,x=-4

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(2 x - 3) (x + 4) = 0

x = \frac{3}{2}, x = - 4

Decimal Notation

x = 1.5, x = - 4

Solution steps

(2 x - 3) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 3 = 0 or x + 4 = 0

Solve

2 x - 3 = 0 : x = \frac{3}{2}

Solve

x + 4 = 0 : x = - 4

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 4

3 x^{2} + 2 x - 7 = 0

3 (2 x \cdot 1) > 4 + 5 (x - 1)

- x^{2} + 6 x - 1 = 0

\frac{24}{x + 4} \leq 6

10 - 2 (3 x + 4) < 11

What are the solutions to the equation (2x-3)(x+4)=0 ?
The solutions to the equation (2x-3)(x+4)=0 are x= 3/2 ,x=-4
Find the zeros of (2x-3)(x+4)=0
The zeros of (2x-3)(x+4)=0 are x= 3/2 ,x=-4