What are the solutions to the equation 12x^2-1=-x ?

The solutions to the equation 12x^2-1=-x are x= 1/4 ,x=-1/3

Find the zeros of 12x^2-1=-x

The zeros of 12x^2-1=-x are x= 1/4 ,x=-1/3

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12 x^{2} - 1 = - x

x = \frac{1}{4}, x = - \frac{1}{3}

Decimal Notation

x = 0.25, x = - 0.33333 \dots

Solution steps

12 x^{2} - 1 = - x

Move

x

to the left side

12 x^{2} - 1 + x = 0

Write in the standard form

a x^{2} + b x + c = 0

12 x^{2} + x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 12 ( - 1 )}{2 \cdot 12}

1^{2} - 4 \cdot 12 (- 1) = 7

x_{1, 2} = \frac{- 1 \pm 7}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 1 + 7}{2 \cdot 12}, x_{2} = \frac{- 1 - 7}{2 \cdot 12}

x = \frac{- 1 + 7}{2 \cdot 12} : \frac{1}{4}

x = \frac{- 1 - 7}{2 \cdot 12} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - \frac{1}{3}

\frac{q}{2} \leq 2

- 20 m^{9} + 18 m^{7} - 8 m^{4} + 2 m^{4} n

4 (x + 3) = 16

n^{3} + 1

4 x^{3} + 32 y^{3}

What are the solutions to the equation 12x^2-1=-x ?
The solutions to the equation 12x^2-1=-x are x= 1/4 ,x=-1/3
Find the zeros of 12x^2-1=-x
The zeros of 12x^2-1=-x are x= 1/4 ,x=-1/3