What is log_{14}(7)+log_{14}(2) ?

The solution to log_{14}(7)+log_{14}(2) is 1

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simplify log_{14}(7)+log_{14}(2)

simplify

lo g_{14} (7) + lo g_{14} (2)

1

Solution steps

lo g_{14} (7) + lo g_{14} (2)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{14} (7) + lo g_{14} (2) = lo g_{14} (7 \cdot 2)

= lo g_{14} (7 \cdot 2)

Multiply the numbers:

7 \cdot 2 = 14

= lo g_{14} (14)

Apply log rule:

lo g_{a} (a) = 1

= 1

5 (3 y + 7) \leq 13 y + 19

(\frac{1}{2})^{3} \cdot (\frac{2}{3})^{2}

(\frac{7}{5})^{2.8}

x ∣ x - 3 ∣ = 2 x ∣ x - 3 ∣

\frac{1}{12} - \frac{1}{2}