What are the solutions to the equation x^2-9x+21=0 ?

The solutions to the equation x^2-9x+21=0 are x= 9/2+i(sqrt(3))/2 ,x= 9/2-i(sqrt(3))/2

Find the zeros of x^2-9x+21=0

The zeros of x^2-9x+21=0 are x= 9/2+i(sqrt(3))/2 ,x= 9/2-i(sqrt(3))/2

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x^{2} - 9 x + 21 = 0

x = \frac{9}{2} + i \frac{3}{2}, x = \frac{9}{2} - i \frac{3}{2}

Solution steps

x^{2} - 9 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

Simplify

(- 9)^{2} - 4 \cdot 1 \cdot 21 : 3 i

x_{1, 2} = \frac{- ( - 9 ) \pm 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 3 i}{2 \cdot 1}

x = \frac{- ( - 9 ) + 3 i}{2 \cdot 1} : \frac{9}{2} + i \frac{3}{2}

x = \frac{- ( - 9 ) - 3 i}{2 \cdot 1} : \frac{9}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{9}{2} + i \frac{3}{2}, x = \frac{9}{2} - i \frac{3}{2}

\frac{x - 1}{x} < 4

- 15 q \leq - 60

x^{2} = 8 x - 1

9 ∣ - 6 n ∣ + 9 = 117

3 x + 5 x = 7

What are the solutions to the equation x^2-9x+21=0 ?
The solutions to the equation x^2-9x+21=0 are x= 9/2+i(sqrt(3))/2 ,x= 9/2-i(sqrt(3))/2
Find the zeros of x^2-9x+21=0
The zeros of x^2-9x+21=0 are x= 9/2+i(sqrt(3))/2 ,x= 9/2-i(sqrt(3))/2