What are the solutions to the equation 2x^2+5x-15=0 ?

The solutions to the equation 2x^2+5x-15=0 are x=(-5+sqrt(145))/4 ,x=(-5-sqrt(145))/4

Find the zeros of 2x^2+5x-15=0

The zeros of 2x^2+5x-15=0 are x=(-5+sqrt(145))/4 ,x=(-5-sqrt(145))/4

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2 x^{2} + 5 x - 15 = 0

x = \frac{- 5 + 145}{4}, x = \frac{- 5 - 145}{4}

Decimal Notation

x = 1.76039 \dots, x = - 4.26039 \dots

Solution steps

2 x^{2} + 5 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 15) = 145

x_{1, 2} = \frac{- 5 \pm 145}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 145}{2 \cdot 2}, x_{2} = \frac{- 5 - 145}{2 \cdot 2}

x = \frac{- 5 + 145}{2 \cdot 2} : \frac{- 5 + 145}{4}

x = \frac{- 5 - 145}{2 \cdot 2} : \frac{- 5 - 145}{4}

The solutions to the quadratic equation are:

x = \frac{- 5 + 145}{4}, x = \frac{- 5 - 145}{4}

\frac{3}{\frac{2}{2}}

20 uv - 60 u^{3} - 5 xv + 15 x u^{2}

2 (3 x + 1) = 20

4 b^{2} + 11 b = 5

6 x > - 12

What are the solutions to the equation 2x^2+5x-15=0 ?
The solutions to the equation 2x^2+5x-15=0 are x=(-5+sqrt(145))/4 ,x=(-5-sqrt(145))/4
Find the zeros of 2x^2+5x-15=0
The zeros of 2x^2+5x-15=0 are x=(-5+sqrt(145))/4 ,x=(-5-sqrt(145))/4