What are the solutions to the equation 4u^2-20u=0 ?

The solutions to the equation 4u^2-20u=0 are u=5,u=0

Find the zeros of 4u^2-20u=0

The zeros of 4u^2-20u=0 are u=5,u=0

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4 u^{2} - 20 u = 0

u = 5, u = 0

Solution steps

4 u^{2} - 20 u = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 0 = 20

u_{1, 2} = \frac{- ( - 20 ) \pm 20}{2 \cdot 4}

Separate the solutions

u_{1} = \frac{- ( - 20 ) + 20}{2 \cdot 4}, u_{2} = \frac{- ( - 20 ) - 20}{2 \cdot 4}

u = \frac{- ( - 20 ) + 20}{2 \cdot 4} : 5

u = \frac{- ( - 20 ) - 20}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

u = 5, u = 0

\frac{5}{6} - \frac{8}{12}

\frac{3}{5} x - 5 = \frac{1}{2} x - 4

5 x^{2} + 14 x + 9

i^{68}

4 (2 k + 1) - 1 = 5

What are the solutions to the equation 4u^2-20u=0 ?
The solutions to the equation 4u^2-20u=0 are u=5,u=0
Find the zeros of 4u^2-20u=0
The zeros of 4u^2-20u=0 are u=5,u=0