What are the solutions to the equation 6z^2-7z-3=0 ?

The solutions to the equation 6z^2-7z-3=0 are z= 3/2 ,z=-1/3

Find the zeros of 6z^2-7z-3=0

The zeros of 6z^2-7z-3=0 are z= 3/2 ,z=-1/3

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6 z^{2} - 7 z - 3 = 0

z = \frac{3}{2}, z = - \frac{1}{3}

Decimal Notation

z = 1.5, z = - 0.33333 \dots

Solution steps

6 z^{2} - 7 z - 3 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 6 ( - 3 )}{2 \cdot 6}

(- 7)^{2} - 4 \cdot 6 (- 3) = 11

z_{1, 2} = \frac{- ( - 7 ) \pm 11}{2 \cdot 6}

Separate the solutions

z_{1} = \frac{- ( - 7 ) + 11}{2 \cdot 6}, z_{2} = \frac{- ( - 7 ) - 11}{2 \cdot 6}

z = \frac{- ( - 7 ) + 11}{2 \cdot 6} : \frac{3}{2}

z = \frac{- ( - 7 ) - 11}{2 \cdot 6} : - \frac{1}{3}

The solutions to the quadratic equation are:

z = \frac{3}{2}, z = - \frac{1}{3}

3 a + 9 = 54

(3 + 2)^{2} \cdot 2

\frac{x}{x - 4} > 5

\frac{x}{7} - \frac{x}{9} = 2

4 x^{4} - 25 x^{2}

What are the solutions to the equation 6z^2-7z-3=0 ?
The solutions to the equation 6z^2-7z-3=0 are z= 3/2 ,z=-1/3
Find the zeros of 6z^2-7z-3=0
The zeros of 6z^2-7z-3=0 are z= 3/2 ,z=-1/3