What is 6^2+24(2)<= ((5x+4x))/2 ?

The solution to 6^2+24(2) = 56/3

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6^2+24(2)<= ((5x+4x))/2

6^{2} + 24 (2) \leq \frac{( 5 x + 4 x )}{2}

x \geq \frac{56}{3}

Interval Notation

[\frac{56}{3}, \infty)

Decimal Notation

x \geq 18.66666 \dots

Solution steps

6^{2} + 24 (2) \leq \frac{( 5 x + 4 x )}{2}

Switch sides

\frac{( 5 x + 4 x )}{2} \geq 6^{2} + 24 (2)

Remove parentheses:

(a) = a

\frac{( 5 x + 4 x )}{2} \geq 6^{2} + 24 \cdot 2

Multiply the numbers:

24 \cdot 2 = 48

\frac{( 5 x + 4 x )}{2} \geq 6^{2} + 48

6^{2} = 36

\frac{( 5 x + 4 x )}{2} \geq 36 + 48

Add the numbers:

36 + 48 = 84

\frac{( 5 x + 4 x )}{2} \geq 84

Multiply both sides by

2

9 x \geq 168

Divide both sides by

9

x \geq \frac{56}{3}

- \frac{10}{- 6}

18 x^{3} y^{2}

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4 x^{2} (3 x - 1) - 3 x + 1

What is 6^2+24(2)<= ((5x+4x))/2 ?
The solution to 6^2+24(2)<= ((5x+4x))/2 is x>= 56/3