What are the solutions to the equation 3x^2+6x+15=10 ?

The solutions to the equation 3x^2+6x+15=10 are x=-1+isqrt(2/3),x=-1-isqrt(2/3)

Find the zeros of 3x^2+6x+15=10

The zeros of 3x^2+6x+15=10 are x=-1+isqrt(2/3),x=-1-isqrt(2/3)

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3 x^{2} + 6 x + 15 = 10

x = - 1 + i \frac{2}{3}, x = - 1 - i \frac{2}{3}

Solution steps

3 x^{2} + 6 x + 15 = 10

Move

10

to the left side

3 x^{2} + 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

Simplify

6^{2} - 4 \cdot 3 \cdot 5 : 26 i

x_{1, 2} = \frac{- 6 \pm 2 6 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 2 6 i}{2 \cdot 3}, x_{2} = \frac{- 6 - 2 6 i}{2 \cdot 3}

x = \frac{- 6 + 2 6 i}{2 \cdot 3} : - 1 + i \frac{2}{3}

x = \frac{- 6 - 2 6 i}{2 \cdot 3} : - 1 - i \frac{2}{3}

The solutions to the quadratic equation are:

x = - 1 + i \frac{2}{3}, x = - 1 - i \frac{2}{3}

in (x^{2})

6 (2 x - 3) + 4 = 16 - (- 18)

r^{2} - 16 r + 48

- 7 x + 2 + 3 x = - 38

What are the solutions to the equation 3x^2+6x+15=10 ?
The solutions to the equation 3x^2+6x+15=10 are x=-1+isqrt(2/3),x=-1-isqrt(2/3)
Find the zeros of 3x^2+6x+15=10
The zeros of 3x^2+6x+15=10 are x=-1+isqrt(2/3),x=-1-isqrt(2/3)