What are the solutions to the equation (x-1)^2=3 ?

The solutions to the equation (x-1)^2=3 are x=sqrt(3)+1,x=-sqrt(3)+1

Find the zeros of (x-1)^2=3

The zeros of (x-1)^2=3 are x=sqrt(3)+1,x=-sqrt(3)+1

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(x - 1)^{2} = 3

x = 3 + 1, x = - 3 + 1

Decimal Notation

x = 2.73205 \dots, x = - 0.73205 \dots

Solution steps

(x - 1)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 3 : x = 3 + 1

Solve

x - 1 = - 3 : x = - 3 + 1

The solutions to the quadratic equation are:

x = 3 + 1, x = - 3 + 1

\frac{ln ( 4 )}{3}

10 - \frac{2}{3} x \leq 18

∣ 2 x + 1 ∣ > 0

2 x \geq 16

\frac{f ( x + h ) - f ( x )}{h}

What are the solutions to the equation (x-1)^2=3 ?
The solutions to the equation (x-1)^2=3 are x=sqrt(3)+1,x=-sqrt(3)+1
Find the zeros of (x-1)^2=3
The zeros of (x-1)^2=3 are x=sqrt(3)+1,x=-sqrt(3)+1