What are the solutions to the equation 6y^2+11y=10 ?

The solutions to the equation 6y^2+11y=10 are y= 2/3 ,y=-5/2

Find the zeros of 6y^2+11y=10

The zeros of 6y^2+11y=10 are y= 2/3 ,y=-5/2

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6 y^{2} + 11 y = 10

y = \frac{2}{3}, y = - \frac{5}{2}

Decimal Notation

y = 0.66666 \dots, y = - 2.5

Solution steps

6 y^{2} + 11 y = 10

Move

10

to the left side

6 y^{2} + 11 y - 10 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 6 ( - 10 )}{2 \cdot 6}

1 1^{2} - 4 \cdot 6 (- 10) = 19

y_{1, 2} = \frac{- 11 \pm 19}{2 \cdot 6}

Separate the solutions

y_{1} = \frac{- 11 + 19}{2 \cdot 6}, y_{2} = \frac{- 11 - 19}{2 \cdot 6}

y = \frac{- 11 + 19}{2 \cdot 6} : \frac{2}{3}

y = \frac{- 11 - 19}{2 \cdot 6} : - \frac{5}{2}

The solutions to the quadratic equation are:

y = \frac{2}{3}, y = - \frac{5}{2}

x^{2} + 3 x - 15 < 0

3 x - 12

\frac{3}{49}

\frac{63}{7}

23 y + 50 + 27 y = 50 y + 50

What are the solutions to the equation 6y^2+11y=10 ?
The solutions to the equation 6y^2+11y=10 are y= 2/3 ,y=-5/2
Find the zeros of 6y^2+11y=10
The zeros of 6y^2+11y=10 are y= 2/3 ,y=-5/2