What are the solutions to the equation 2x^2+6x+1=0 ?

The solutions to the equation 2x^2+6x+1=0 are x=(-3+sqrt(7))/2 ,x=-(3+sqrt(7))/2

Find the zeros of 2x^2+6x+1=0

The zeros of 2x^2+6x+1=0 are x=(-3+sqrt(7))/2 ,x=-(3+sqrt(7))/2

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2 x^{2} + 6 x + 1 = 0

x = \frac{- 3 + 7}{2}, x = - \frac{3 + 7}{2}

Decimal Notation

x = - 0.17712 \dots, x = - 2.82287 \dots

Solution steps

2 x^{2} + 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 \cdot 1}{2 \cdot 2}

6^{2} - 4 \cdot 2 \cdot 1 = 27

x_{1, 2} = \frac{- 6 \pm 2 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 6 + 2 7}{2 \cdot 2}, x_{2} = \frac{- 6 - 2 7}{2 \cdot 2}

x = \frac{- 6 + 2 7}{2 \cdot 2} : \frac{- 3 + 7}{2}

x = \frac{- 6 - 2 7}{2 \cdot 2} : - \frac{3 + 7}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 7}{2}, x = - \frac{3 + 7}{2}

\frac{y ^{4} + 5 y ^{2} + 6}{4 y ^{5} + 12 y ^{3}}

x^{4} + 3 x^{3} - x^{2} + x + 4

\frac{9}{- 4 i}

- 3 x^{2} + 6 x + 24

\frac{9}{36}

What are the solutions to the equation 2x^2+6x+1=0 ?
The solutions to the equation 2x^2+6x+1=0 are x=(-3+sqrt(7))/2 ,x=-(3+sqrt(7))/2
Find the zeros of 2x^2+6x+1=0
The zeros of 2x^2+6x+1=0 are x=(-3+sqrt(7))/2 ,x=-(3+sqrt(7))/2