What are the solutions to the equation (2x+5)^2=81 ?

The solutions to the equation (2x+5)^2=81 are x=2,x=-7

Find the zeros of (2x+5)^2=81

The zeros of (2x+5)^2=81 are x=2,x=-7

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(2 x + 5)^{2} = 81

x = 2, x = - 7

Solution steps

(2 x + 5)^{2} = 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 5 = 81 : x = 2

Solve

2 x + 5 = - 81 : x = - 7

The solutions to the quadratic equation are:

x = 2, x = - 7

∣ 3 m - 2 ∣ = 0

5 - ∣ 3 x - 2 ∣ = - 3

2^{4}

x^{5} - x^{4} + 2 x^{3} + 22 x^{2} - 35 x + 75

lo g_{4} (2)

What are the solutions to the equation (2x+5)^2=81 ?
The solutions to the equation (2x+5)^2=81 are x=2,x=-7
Find the zeros of (2x+5)^2=81
The zeros of (2x+5)^2=81 are x=2,x=-7