What are the solutions to the equation (x-3)^2=9 ?

The solutions to the equation (x-3)^2=9 are x=6,x=0

Find the zeros of (x-3)^2=9

The zeros of (x-3)^2=9 are x=6,x=0

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(x - 3)^{2} = 9

x = 6, x = 0

Solution steps

(x - 3)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 9 : x = 6

Solve

x - 3 = - 9 : x = 0

The solutions to the quadratic equation are:

x = 6, x = 0

\frac{5 + x}{5 - x} \geq 1

2 (5 x - 8) = 7 - (5 - x)

2 7^{\frac{1}{4}} \cdot 3^{\frac{1}{4}}

- 21 x^{2} + 21 = 0

\frac{x}{7} - 3 = \frac{x}{7}

What are the solutions to the equation (x-3)^2=9 ?
The solutions to the equation (x-3)^2=9 are x=6,x=0
Find the zeros of (x-3)^2=9
The zeros of (x-3)^2=9 are x=6,x=0