What are the solutions to the equation 4x^2+4x=-1 ?

The solutions to the equation 4x^2+4x=-1 are x=-1/2

Find the zeros of 4x^2+4x=-1

The zeros of 4x^2+4x=-1 are x=-1/2

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4 x^{2} + 4 x = - 1

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

4 x^{2} + 4 x = - 1

Move

1

to the left side

4 x^{2} + 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

4^{2} - 4 \cdot 4 \cdot 1 = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 4}

x = \frac{- 4}{2 \cdot 4}

\frac{- 4}{2 \cdot 4} = - \frac{1}{2}

x = - \frac{1}{2}

The solution to the quadratic equation is:

x = - \frac{1}{2}

2 y^{2} + 8 y - 6 = 3 y

- 4 x - 7 \geq 21

5.5 x + 6.25 (100) = 6 (x + 100)

x^{2} + 10 x \geq - 24

\frac{π}{3} - \frac{π}{3}

What are the solutions to the equation 4x^2+4x=-1 ?
The solutions to the equation 4x^2+4x=-1 are x=-1/2
Find the zeros of 4x^2+4x=-1
The zeros of 4x^2+4x=-1 are x=-1/2