What are the solutions to the equation 4x-3x^2=5 ?

The solutions to the equation 4x-3x^2=5 are x= 2/3-i(sqrt(11))/3 ,x= 2/3+i(sqrt(11))/3

Find the zeros of 4x-3x^2=5

The zeros of 4x-3x^2=5 are x= 2/3-i(sqrt(11))/3 ,x= 2/3+i(sqrt(11))/3

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4 x - 3 x^{2} = 5

x = \frac{2}{3} - i \frac{11}{3}, x = \frac{2}{3} + i \frac{11}{3}

Solution steps

4 x - 3 x^{2} = 5

Move

5

to the left side

4 x - 3 x^{2} - 5 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 x^{2} + 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 3 ) ( - 5 )}{2 ( - 3 )}

Simplify

4^{2} - 4 (- 3) (- 5) : 211 i

x_{1, 2} = \frac{- 4 \pm 2 11 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 11 i}{2 ( - 3 )}, x_{2} = \frac{- 4 - 2 11 i}{2 ( - 3 )}

x = \frac{- 4 + 2 11 i}{2 ( - 3 )} : \frac{2}{3} - i \frac{11}{3}

x = \frac{- 4 - 2 11 i}{2 ( - 3 )} : \frac{2}{3} + i \frac{11}{3}

The solutions to the quadratic equation are:

x = \frac{2}{3} - i \frac{11}{3}, x = \frac{2}{3} + i \frac{11}{3}

a^{2} + a - ab - b

u^{2} v^{2} - w^{2}

m^{2} + 10 m + 21

∣ 9 x + 3 ∣ + 7 < 3

3 + \frac{5}{8} x \leq 5

What are the solutions to the equation 4x-3x^2=5 ?
The solutions to the equation 4x-3x^2=5 are x= 2/3-i(sqrt(11))/3 ,x= 2/3+i(sqrt(11))/3
Find the zeros of 4x-3x^2=5
The zeros of 4x-3x^2=5 are x= 2/3-i(sqrt(11))/3 ,x= 2/3+i(sqrt(11))/3