What is (-2+3i)/((4+2i)(-1+i)) ?

The solution to (-2+3i)/((4+2i)(-1+i)) is 9/20-7/20 i

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simplify (-2+3i)/((4+2i)(-1+i))

simplify

\frac{- 2 + 3 i}{( 4 + 2 i ) ( - 1 + i )}

\frac{9}{20} - \frac{7}{20} i

Solution steps

\frac{- 2 + 3 i}{( 4 + 2 i ) ( - 1 + i )}

(4 + 2 i) (- 1 + i) = - 6 + 2 i

= \frac{- 2 + 3 i}{- 6 + 2 i}

Multiply by the conjugate

\frac{- 6 - 2 i}{- 6 - 2 i}

= \frac{( - 2 + 3 i ) ( - 6 - 2 i )}{( - 6 + 2 i ) ( - 6 - 2 i )}

Simplify

\frac{( - 2 + 3 i ) ( - 6 - 2 i )}{( - 6 + 2 i ) ( - 6 - 2 i )} : \frac{18 - 14 i}{40}

= \frac{18 - 14 i}{40}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{18}{40} + \frac{- 14}{40} i

Simplify

\frac{18}{40} + \frac{- 14}{40} i : \frac{9}{20} - \frac{7}{20} i

= \frac{9}{20} - \frac{7}{20} i

- 2 z - 2 \geq 8

17 \cdot 7

4.1 (t + 1) = 12.3

\frac{32 a ^{13} b ^{8} c ^{9}}{64 a ^{10} b ^{6}}

6 2^{x + 3} \leq 7^{2 x + 1}

What is (-2+3i)/((4+2i)(-1+i)) ?
The solution to (-2+3i)/((4+2i)(-1+i)) is 9/20-7/20 i