What is sqrt((3^{-1)+6^{-1})/(8^{-1)}} ?

The solution to sqrt((3^{-1)+6^{-1})/(8^{-1)}} is 2

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simplify sqrt((3^{-1)+6^{-1})/(8^{-1)}}

simplify

\frac{3 ^{- 1} + 6 ^{- 1}}{8 ^{- 1}}

2

Solution steps

\frac{3 ^{- 1} + 6 ^{- 1}}{8 ^{- 1}}

Apply radical rule:

\frac{a}{b} = \frac{a}{b}, a \geq 0, b \geq 0

= \frac{3 ^{- 1} + 6 ^{- 1}}{8 ^{- 1}}

3^{- 1} + 6^{- 1} = \frac{1}{2}

= \frac{\frac{1}{2}}{8 ^{- 1}}

8^{- 1} = \frac{1}{2 2}

= \frac{\frac{1}{2}}{\frac{1}{2 2}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{1 \cdot 2 2}{2 \cdot 1}

Cancel

\frac{1 \cdot 2 2}{2 \cdot 1} : 2

= 2

8 x^{2} + 28 x y

x = \frac{ln ( \frac{185}{290} )}{4}

399

a^{3} - 8 a^{2} + 30 a - 56

x^{4} - x^{3} - 20 x^{2}

What is sqrt((3^{-1)+6^{-1})/(8^{-1)}} ?
The solution to sqrt((3^{-1)+6^{-1})/(8^{-1)}} is 2