What are the solutions to the equation (3x-4)^2=21 ?

The solutions to the equation (3x-4)^2=21 are x=(sqrt(21)+4)/3 ,x=(-sqrt(21)+4)/3

Find the zeros of (3x-4)^2=21

The zeros of (3x-4)^2=21 are x=(sqrt(21)+4)/3 ,x=(-sqrt(21)+4)/3

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(3 x - 4)^{2} = 21

x = \frac{21 + 4}{3}, x = \frac{- 21 + 4}{3}

Decimal Notation

x = 2.86085 \dots, x = - 0.19419 \dots

Solution steps

(3 x - 4)^{2} = 21

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 4 = 21 : x = \frac{21 + 4}{3}

Solve

3 x - 4 = - 21 : x = \frac{- 21 + 4}{3}

The solutions to the quadratic equation are:

x = \frac{21 + 4}{3}, x = \frac{- 21 + 4}{3}

3 x - 1 < 9

y^{2} - \frac{1}{9} = 0

x^{2} - 3 x + 2 x y - 6 y

x + 20 = 3 x

4 (x - 3) - 8 < 5 - x

What are the solutions to the equation (3x-4)^2=21 ?
The solutions to the equation (3x-4)^2=21 are x=(sqrt(21)+4)/3 ,x=(-sqrt(21)+4)/3
Find the zeros of (3x-4)^2=21
The zeros of (3x-4)^2=21 are x=(sqrt(21)+4)/3 ,x=(-sqrt(21)+4)/3