What are the solutions to the equation -16x^2+64=0 ?

The solutions to the equation -16x^2+64=0 are x=2,x=-2

Find the zeros of -16x^2+64=0

The zeros of -16x^2+64=0 are x=2,x=-2

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- 16 x^{2} + 64 = 0

x = 2, x = - 2

Solution steps

- 16 x^{2} + 64 = 0

Move

64

to the right side

- 16 x^{2} = - 64

Divide both sides by

- 16

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

2 x^{2} - x y - y^{2}

- 3 x^{2} - 8 - 10 x = 3

3 - 6 x \geq 16

(x - 3)^{2} = 25

8 (u - 1) - 4 = 4 (2 u - 3)

What are the solutions to the equation -16x^2+64=0 ?
The solutions to the equation -16x^2+64=0 are x=2,x=-2
Find the zeros of -16x^2+64=0
The zeros of -16x^2+64=0 are x=2,x=-2