What are the solutions to the equation x^2-0.3x-0.04=0 ?

The solutions to the equation x^2-0.3x-0.04=0 are x= 2/5 ,x=-1/10

Find the zeros of x^2-0.3x-0.04=0

The zeros of x^2-0.3x-0.04=0 are x= 2/5 ,x=-1/10

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x^{2} - 0.3 x - 0.04 = 0

x = \frac{2}{5}, x = - \frac{1}{10}

Decimal Notation

x = 0.4, x = - 0.1

Solution steps

x^{2} - 0.3 x - 0.04 = 0

Multiply both sides by

100

100 x^{2} - 30 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 100 ( - 4 )}{2 \cdot 100}

(- 30)^{2} - 4 \cdot 100 (- 4) = 50

x_{1, 2} = \frac{- ( - 30 ) \pm 50}{2 \cdot 100}

Separate the solutions

x_{1} = \frac{- ( - 30 ) + 50}{2 \cdot 100}, x_{2} = \frac{- ( - 30 ) - 50}{2 \cdot 100}

x = \frac{- ( - 30 ) + 50}{2 \cdot 100} : \frac{2}{5}

x = \frac{- ( - 30 ) - 50}{2 \cdot 100} : - \frac{1}{10}

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = - \frac{1}{10}

- 0.2 x^{2} - 1 0^{- 4.7} x + 1 0^{- 4.7} = 0

- 6 + 9 ∣ x + 3 ∣ = 12

10 \cdot 6^{x} \leq 2 \cdot 6^{- x} - 8

- 4 (- 2 x - 2) + x - 2 = - 48

\frac{\frac{2}{k + 2} - 1}{\frac{2}{k + 2} + 1}

What are the solutions to the equation x^2-0.3x-0.04=0 ?
The solutions to the equation x^2-0.3x-0.04=0 are x= 2/5 ,x=-1/10
Find the zeros of x^2-0.3x-0.04=0
The zeros of x^2-0.3x-0.04=0 are x= 2/5 ,x=-1/10