What are the solutions to the equation x^2-12x+31=0 ?

The solutions to the equation x^2-12x+31=0 are x=6+sqrt(5),x=6-sqrt(5)

Find the zeros of x^2-12x+31=0

The zeros of x^2-12x+31=0 are x=6+sqrt(5),x=6-sqrt(5)

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x^{2} - 12 x + 31 = 0

x = 6 + 5, x = 6 - 5

Solution steps

x^{2} - 12 x + 31 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 31}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 31 = 25

x_{1, 2} = \frac{- ( - 12 ) \pm 2 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 5}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2 5}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2 5}{2 \cdot 1} : 6 + 5

x = \frac{- ( - 12 ) - 2 5}{2 \cdot 1} : 6 - 5

The solutions to the quadratic equation are:

x = 6 + 5, x = 6 - 5

2 y + (- 23) = - 10 - (- 39)

u^{2} = 16 u + 36

4 (2 a + 3) < 3 (a - 1)

5 - 2 x = \frac{3}{2} x - 2

3 (- x - 3) + x - 3 = - 24

What are the solutions to the equation x^2-12x+31=0 ?
The solutions to the equation x^2-12x+31=0 are x=6+sqrt(5),x=6-sqrt(5)
Find the zeros of x^2-12x+31=0
The zeros of x^2-12x+31=0 are x=6+sqrt(5),x=6-sqrt(5)