What are the solutions to the equation 2x^2+17x-9=0 ?

The solutions to the equation 2x^2+17x-9=0 are x= 1/2 ,x=-9

Find the zeros of 2x^2+17x-9=0

The zeros of 2x^2+17x-9=0 are x= 1/2 ,x=-9

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2 x^{2} + 17 x - 9 = 0

x = \frac{1}{2}, x = - 9

Solution steps

2 x^{2} + 17 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

1 7^{2} - 4 \cdot 2 (- 9) = 19

x_{1, 2} = \frac{- 17 \pm 19}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 17 + 19}{2 \cdot 2}, x_{2} = \frac{- 17 - 19}{2 \cdot 2}

x = \frac{- 17 + 19}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 17 - 19}{2 \cdot 2} : - 9

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 9

- 3 x x_{+} 5 (x - 2)

- 2 x = 10

\frac{4}{3} (6)

\frac{a - 7}{a ^{2} - 3 a - 28} \cdot \frac{8 a - 40}{a ^{2} + 3 a - 40}

x^{2} - 7 x y - 8 y^{2}

What are the solutions to the equation 2x^2+17x-9=0 ?
The solutions to the equation 2x^2+17x-9=0 are x= 1/2 ,x=-9
Find the zeros of 2x^2+17x-9=0
The zeros of 2x^2+17x-9=0 are x= 1/2 ,x=-9