What are the solutions to the equation n^2+5n-6=0 ?

The solutions to the equation n^2+5n-6=0 are n=1,n=-6

Find the zeros of n^2+5n-6=0

The zeros of n^2+5n-6=0 are n=1,n=-6

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n^{2} + 5 n - 6 = 0

n = 1, n = - 6

Solution steps

n^{2} + 5 n - 6 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 6) = 7

n_{1, 2} = \frac{- 5 \pm 7}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 5 + 7}{2 \cdot 1}, n_{2} = \frac{- 5 - 7}{2 \cdot 1}

n = \frac{- 5 + 7}{2 \cdot 1} : 1

n = \frac{- 5 - 7}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

n = 1, n = - 6

- 16 = - 16

9 n + 16 \leq 22 + 7 n

x^{2} > 2 - 6 x

7!

\frac{1}{x} > 2

What are the solutions to the equation n^2+5n-6=0 ?
The solutions to the equation n^2+5n-6=0 are n=1,n=-6
Find the zeros of n^2+5n-6=0
The zeros of n^2+5n-6=0 are n=1,n=-6