What are the solutions to the equation -7x^2+14x+21=0 ?

The solutions to the equation -7x^2+14x+21=0 are x=-1,x=3

Find the zeros of -7x^2+14x+21=0

The zeros of -7x^2+14x+21=0 are x=-1,x=3

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- 7 x^{2} + 14 x + 21 = 0

x = - 1, x = 3

Solution steps

- 7 x^{2} + 14 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 ( - 7 ) \cdot 21}{2 ( - 7 )}

1 4^{2} - 4 (- 7) \cdot 21 = 28

x_{1, 2} = \frac{- 14 \pm 28}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- 14 + 28}{2 ( - 7 )}, x_{2} = \frac{- 14 - 28}{2 ( - 7 )}

x = \frac{- 14 + 28}{2 ( - 7 )} : - 1

x = \frac{- 14 - 28}{2 ( - 7 )} : 3

The solutions to the quadratic equation are:

x = - 1, x = 3

g^{2} + 11 g + 24

\frac{a}{a ^{2} - 4} - \frac{1}{a - 2}

x^{2} + 5 x - 104

35 - 22 x + 6 - 18 x = 14 - 30 x + 32

6 x - 12 = 6 (x - 2)

What are the solutions to the equation -7x^2+14x+21=0 ?
The solutions to the equation -7x^2+14x+21=0 are x=-1,x=3
Find the zeros of -7x^2+14x+21=0
The zeros of -7x^2+14x+21=0 are x=-1,x=3