What are the solutions to the equation 9(2m-3)^2+8=449 ?

The solutions to the equation 9(2m-3)^2+8=449 are m=5,m=-2

Find the zeros of 9(2m-3)^2+8=449

The zeros of 9(2m-3)^2+8=449 are m=5,m=-2

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9 (2 m - 3)^{2} + 8 = 449

m = 5, m = - 2

Solution steps

9 (2 m - 3)^{2} + 8 = 449

Move

8

to the right side

9 (2 m - 3)^{2} = 441

Divide both sides by

9

(2 m - 3)^{2} = 49

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 m - 3 = 49 : m = 5

Solve

2 m - 3 = - 49 : m = - 2

The solutions to the quadratic equation are:

m = 5, m = - 2

(3 + 2 i) (3 - 2 i)

\frac{x + 1}{2} = \frac{x}{7}

6 x y - 3 x - 8 y + 4

p - 5 < 3

x^{2} y^{2} - 9 z^{4}

What are the solutions to the equation 9(2m-3)^2+8=449 ?
The solutions to the equation 9(2m-3)^2+8=449 are m=5,m=-2
Find the zeros of 9(2m-3)^2+8=449
The zeros of 9(2m-3)^2+8=449 are m=5,m=-2