What are the solutions to the equation 4x^2-16x+11=0 ?

The solutions to the equation 4x^2-16x+11=0 are x=(4+sqrt(5))/2 ,x=(4-sqrt(5))/2

Find the zeros of 4x^2-16x+11=0

The zeros of 4x^2-16x+11=0 are x=(4+sqrt(5))/2 ,x=(4-sqrt(5))/2

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4 x^{2} - 16 x + 11 = 0

x = \frac{4 + 5}{2}, x = \frac{4 - 5}{2}

Decimal Notation

x = 3.11803 \dots, x = 0.88196 \dots

Solution steps

4 x^{2} - 16 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 4 \cdot 11}{2 \cdot 4}

(- 16)^{2} - 4 \cdot 4 \cdot 11 = 45

x_{1, 2} = \frac{- ( - 16 ) \pm 4 5}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 5}{2 \cdot 4}, x_{2} = \frac{- ( - 16 ) - 4 5}{2 \cdot 4}

x = \frac{- ( - 16 ) + 4 5}{2 \cdot 4} : \frac{4 + 5}{2}

x = \frac{- ( - 16 ) - 4 5}{2 \cdot 4} : \frac{4 - 5}{2}

The solutions to the quadratic equation are:

x = \frac{4 + 5}{2}, x = \frac{4 - 5}{2}

343 x^{3} + y^{9}

(x + 2) (x - 3) > 2 - x

a^{2} b^{2} + a

7.9 + x = 16.3

2 (\frac{4}{3})^{2} + 5 (\frac{4}{3}) + 6

What are the solutions to the equation 4x^2-16x+11=0 ?
The solutions to the equation 4x^2-16x+11=0 are x=(4+sqrt(5))/2 ,x=(4-sqrt(5))/2
Find the zeros of 4x^2-16x+11=0
The zeros of 4x^2-16x+11=0 are x=(4+sqrt(5))/2 ,x=(4-sqrt(5))/2