What are the solutions to the equation p^2+p-90=0 ?

The solutions to the equation p^2+p-90=0 are p=9,p=-10

Find the zeros of p^2+p-90=0

The zeros of p^2+p-90=0 are p=9,p=-10

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p^{2} + p - 90 = 0

p = 9, p = - 10

Solution steps

p^{2} + p - 90 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 90 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 90) = 19

p_{1, 2} = \frac{- 1 \pm 19}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 1 + 19}{2 \cdot 1}, p_{2} = \frac{- 1 - 19}{2 \cdot 1}

p = \frac{- 1 + 19}{2 \cdot 1} : 9

p = \frac{- 1 - 19}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

p = 9, p = - 10

(2 x - 3) (x + 1) = 0

x^{2} + 5 x = - 2

\frac{3}{5} \cdot 8

\frac{\frac{3}{2}}{2}

lo g_{5} (625) = y

What are the solutions to the equation p^2+p-90=0 ?
The solutions to the equation p^2+p-90=0 are p=9,p=-10
Find the zeros of p^2+p-90=0
The zeros of p^2+p-90=0 are p=9,p=-10