What are the solutions to the equation c^2+14c-5=0 ?

The solutions to the equation c^2+14c-5=0 are c=-7+3sqrt(6),c=-7-3sqrt(6)

Find the zeros of c^2+14c-5=0

The zeros of c^2+14c-5=0 are c=-7+3sqrt(6),c=-7-3sqrt(6)

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c^{2} + 14 c - 5 = 0

c = - 7 + 36, c = - 7 - 36

Solution steps

c^{2} + 14 c - 5 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot (- 5) = 66

c_{1, 2} = \frac{- 14 \pm 6 6}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- 14 + 6 6}{2 \cdot 1}, c_{2} = \frac{- 14 - 6 6}{2 \cdot 1}

c = \frac{- 14 + 6 6}{2 \cdot 1} : - 7 + 36

c = \frac{- 14 - 6 6}{2 \cdot 1} : - 7 - 36

The solutions to the quadratic equation are:

c = - 7 + 36, c = - 7 - 36

2222 - 95 (t) + 1 (t)^{2} < 0

x^{3} - a^{3}

81 - 49 x^{2}

4 w^{2} + 12 w = - 5

5 - 2 x < 7

What are the solutions to the equation c^2+14c-5=0 ?
The solutions to the equation c^2+14c-5=0 are c=-7+3sqrt(6),c=-7-3sqrt(6)
Find the zeros of c^2+14c-5=0
The zeros of c^2+14c-5=0 are c=-7+3sqrt(6),c=-7-3sqrt(6)