What are the solutions to the equation (x+11)(x+5)=-4 ?

The solutions to the equation (x+11)(x+5)=-4 are x=-8+sqrt(5),x=-8-sqrt(5)

Find the zeros of (x+11)(x+5)=-4

The zeros of (x+11)(x+5)=-4 are x=-8+sqrt(5),x=-8-sqrt(5)

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(x + 11) (x + 5) = - 4

x = - 8 + 5, x = - 8 - 5

Solution steps

(x + 11) (x + 5) = - 4

Expand

(x + 11) (x + 5) : x^{2} + 16 x + 55

x^{2} + 16 x + 55 = - 4

Move

4

to the left side

x^{2} + 16 x + 59 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 59}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 59 = 25

x_{1, 2} = \frac{- 16 \pm 2 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 2 5}{2 \cdot 1}, x_{2} = \frac{- 16 - 2 5}{2 \cdot 1}

x = \frac{- 16 + 2 5}{2 \cdot 1} : - 8 + 5

x = \frac{- 16 - 2 5}{2 \cdot 1} : - 8 - 5

The solutions to the quadratic equation are:

x = - 8 + 5, x = - 8 - 5

ln (x - 11) < 0

(- 3)^{- 4}

12 x^{2} - 17 x - 5

- 4 \cdot \frac{2}{3}

- 64 - 24 q

What are the solutions to the equation (x+11)(x+5)=-4 ?
The solutions to the equation (x+11)(x+5)=-4 are x=-8+sqrt(5),x=-8-sqrt(5)
Find the zeros of (x+11)(x+5)=-4
The zeros of (x+11)(x+5)=-4 are x=-8+sqrt(5),x=-8-sqrt(5)