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Popular >

simplify (3i)(-2i)(5i)

Solution

simplify

(3 i) (- 2 i) (5 i)

Solution

30 i

Solution steps

(3 i) (- 2 i) (5 i)

Apply rule:

a (- b) = - ab

(3 i) (- 2 i) = - 3 i 2 i

= - 3 i 2 i 5 i

Multiply the numbers:

- 3 \cdot 2 \cdot 5 = - 30

= - 30 iii

Apply exponent rule:

aaa = a^{3}

iii = i^{3}

= - 30 i^{3}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

i^{3} = i^{2} i

= - 30 i^{2} i

Apply imaginary number rule:

i^{2} = - 1

= - 30 (- 1 i)

Apply rule:

1 \cdot a = a

- 1 i = - i

= - 30 (- i)

Apply rule:

- a (- b) = ab

- 30 (- i) = 30 i

= 30 i

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\frac{1}{3} x + \frac{1}{5} = - 5

∣ x + 5 ∣ < 7

3 x^{2} - 23 x - 70 < 0

\frac{x}{4} = \frac{9}{6}

Frequently Asked Questions (FAQ)

What is (3i)(-2i)(5i) ?
The solution to (3i)(-2i)(5i) is 30i