What are the solutions to the equation 3x^2-3x+5=0 ?

The solutions to the equation 3x^2-3x+5=0 are x= 1/2+i(sqrt(51))/6 ,x= 1/2-i(sqrt(51))/6

Find the zeros of 3x^2-3x+5=0

The zeros of 3x^2-3x+5=0 are x= 1/2+i(sqrt(51))/6 ,x= 1/2-i(sqrt(51))/6

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3 x^{2} - 3 x + 5 = 0

x = \frac{1}{2} + i \frac{51}{6}, x = \frac{1}{2} - i \frac{51}{6}

Solution steps

3 x^{2} - 3 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

Simplify

(- 3)^{2} - 4 \cdot 3 \cdot 5 : 51 i

x_{1, 2} = \frac{- ( - 3 ) \pm 51 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 51 i}{2 \cdot 3}, x_{2} = \frac{- ( - 3 ) - 51 i}{2 \cdot 3}

x = \frac{- ( - 3 ) + 51 i}{2 \cdot 3} : \frac{1}{2} + i \frac{51}{6}

x = \frac{- ( - 3 ) - 51 i}{2 \cdot 3} : \frac{1}{2} - i \frac{51}{6}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{51}{6}, x = \frac{1}{2} - i \frac{51}{6}

x^{2} - 14 x + 53 = 9

- (3 x - 12) = 9 x - 4

9 x - 4 x + 4 \geq 36 - 12

5 x^{3} + 12 x^{2} - 9 x

18 u^{2} - 3 uv - 36 v^{2}

What are the solutions to the equation 3x^2-3x+5=0 ?
The solutions to the equation 3x^2-3x+5=0 are x= 1/2+i(sqrt(51))/6 ,x= 1/2-i(sqrt(51))/6
Find the zeros of 3x^2-3x+5=0
The zeros of 3x^2-3x+5=0 are x= 1/2+i(sqrt(51))/6 ,x= 1/2-i(sqrt(51))/6