What are the solutions to the equation 9x^2+49=0 ?

The solutions to the equation 9x^2+49=0 are x= 7/3 i,x=-7/3 i

Find the zeros of 9x^2+49=0

The zeros of 9x^2+49=0 are x= 7/3 i,x=-7/3 i

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9 x^{2} + 49 = 0

x = \frac{7}{3} i, x = - \frac{7}{3} i

Solution steps

9 x^{2} + 49 = 0

Move

49

to the right side

9 x^{2} = - 49

Divide both sides by

9

x^{2} = - \frac{49}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{49}{9}, x = - - \frac{49}{9}

- \frac{49}{9} = \frac{7}{3} i

- - \frac{49}{9} = - \frac{7}{3} i

x = \frac{7}{3} i, x = - \frac{7}{3} i

3 v = \frac{9}{5}

\frac{- 4 x - 2}{3} = - 6

5 + x = 3

\frac{x}{7} + \frac{x}{5} = - 2

6 x^{2} - 19 x y + 10 y^{2}

What are the solutions to the equation 9x^2+49=0 ?
The solutions to the equation 9x^2+49=0 are x= 7/3 i,x=-7/3 i
Find the zeros of 9x^2+49=0
The zeros of 9x^2+49=0 are x= 7/3 i,x=-7/3 i