What is 2sqrt(x-8)<24 ?

The solution to 2sqrt(x-8)<24 is 8<= x<152

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2sqrt(x-8)<24

2 x - 8 < 24

8 \leq x < 152

Interval Notation

[8, 152)

Solution steps

2 x - 8 < 24

Divide both sides by

2

\frac{2 x - 8}{2} < \frac{24}{2}

Simplify

x - 8 < 12

Square both sides

(x - 8)^{2} < 1 2^{2}

Simplify

x - 8 < 144

Move

8

to the right side

x < 152

Find singularity points

Find non-negative values for radicals:

x \geq 8

Combine the intervals

x < 152 and x \geq 8

Merge Overlapping Intervals

8 \leq x < 152

\frac{2 + 5 i}{- i}

(\frac{1}{2})^{2} - 4

520

5300 x^{2} - 827.8 x + 11.872 = 0

n^{2} + n - 72