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The solutions to the quadratic equation are:
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What are the solutions to the equation (7x+2)^2=27 ?
The solutions to the equation (7x+2)^2=27 are x=(3sqrt(3)-2)/7 ,x=(-3sqrt(3)-2)/7Find the zeros of (7x+2)^2=27
The zeros of (7x+2)^2=27 are x=(3sqrt(3)-2)/7 ,x=(-3sqrt(3)-2)/7