What are the solutions to the equation (7x+2)^2=27 ?

The solutions to the equation (7x+2)^2=27 are x=(3sqrt(3)-2)/7 ,x=(-3sqrt(3)-2)/7

Find the zeros of (7x+2)^2=27

The zeros of (7x+2)^2=27 are x=(3sqrt(3)-2)/7 ,x=(-3sqrt(3)-2)/7

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(7 x + 2)^{2} = 27

x = \frac{3 3 - 2}{7}, x = \frac{- 3 3 - 2}{7}

Solution steps

(7 x + 2)^{2} = 27

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

7 x + 2 = 27 : x = \frac{3 3 - 2}{7}

Solve

7 x + 2 = - 27 : x = \frac{- 3 3 - 2}{7}

The solutions to the quadratic equation are:

x = \frac{3 3 - 2}{7}, x = \frac{- 3 3 - 2}{7}

\frac{z}{1 - i} + \frac{2}{i} = 3

3 x^{- 2} y^{- 5}

1050

\frac{- 8 \cdot 1 0 ^{7}}{- 4 \cdot 1 0 ^{6}}

\frac{2}{3} = \frac{4}{5} k

What are the solutions to the equation (7x+2)^2=27 ?
The solutions to the equation (7x+2)^2=27 are x=(3sqrt(3)-2)/7 ,x=(-3sqrt(3)-2)/7
Find the zeros of (7x+2)^2=27
The zeros of (7x+2)^2=27 are x=(3sqrt(3)-2)/7 ,x=(-3sqrt(3)-2)/7