What are the solutions to the equation 3x^2-2=5 ?

The solutions to the equation 3x^2-2=5 are x=sqrt(7/3),x=-sqrt(7/3)

Find the zeros of 3x^2-2=5

The zeros of 3x^2-2=5 are x=sqrt(7/3),x=-sqrt(7/3)

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3 x^{2} - 2 = 5

x = \frac{7}{3}, x = - \frac{7}{3}

Solution steps

3 x^{2} - 2 = 5

Move

2

to the right side

3 x^{2} = 7

Divide both sides by

3

x^{2} = \frac{7}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{7}{3}, x = - \frac{7}{3}

5 (x + 1) = 35

∣ x + 1 ∣ \geq 7

- \frac{5}{2} x = 15

4 y - 5 + y = 10

- 2 (x - 9) (x + 7) = 0

What are the solutions to the equation 3x^2-2=5 ?
The solutions to the equation 3x^2-2=5 are x=sqrt(7/3),x=-sqrt(7/3)
Find the zeros of 3x^2-2=5
The zeros of 3x^2-2=5 are x=sqrt(7/3),x=-sqrt(7/3)